document.write( "Question 1136603: Let X and Y represent discrete random variables with \"f%28x%2Cy%29=%28xy%2F18%29\" for x ∈ {1,2,3} and y ∈ {1,2}. Compute P(X = 1 and Y = 2) and P(X +Y = 4). \n" ); document.write( "
Algebra.Com's Answer #754390 by ikleyn(52931)\"\" \"About 
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document.write( "    Let X and Y represent discrete random variables with probability density function \"f%28x%2Cy%29=%28xy%2F18%29\" for x ∈ {1,2,3} and y ∈ {1,2}. \r\n" );
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document.write( "    Compute P(X = 1 and Y = 2) and P(X +Y = 4).\r\n" );
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document.write( "(a)  P(X = 1 and Y = 2) = f(1,2) = \"%281%2A2%29%2F18\" = \"2%2F18\" = \"1%2F9\".    ANSWER\r\n" );
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document.write( "(b)  Notice that  X + Y = 4 is possible only if  (X=3 AND Y=1)  OR  (X=2 AND Y=2).\r\n" );
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document.write( "     Therefore,\r\n" );
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document.write( "     P(X + Y = 4) = P(X=3 AND Y=1) + P(X=2 AND Y=2) = f(3,1) + f(2,2) = \"%283%2A1%29%2F18\" + \"%282%2A2%29%2F18\" = \"%283%2B4%29%2F18\" = \"7%2F18\".    ANSWER\r\n" );
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