document.write( "Question 1136563: Four years ago a man was 6times as old as his son.In twelve years time the man will be twice as old as his son.find their present ages.
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Algebra.Com's Answer #754344 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Let x be the son's age 4 years ago.
\n" ); document.write( "Then 6x = the man's age 4 years ago.

\n" ); document.write( "x+16 is the age of the son 12 years from now (16 years after 4 years ago);
\n" ); document.write( "6x+16 is the man's age 12 years from now.

\n" ); document.write( "In 12 years, the man's age will be twice the son's age:

\n" ); document.write( " $\"6x%2B16+=+2%28x%2B16%29\"$
\n" ); document.write( " $\"6x%2B16+=+2x%2B32\"$
\n" ); document.write( " $\"4x+=+16\"$
\n" ); document.write( " $\"x+=+4\"$

\n" ); document.write( "4 years ago, the son's age was x=4 and the man's age was 6x = 24.

\n" ); document.write( "Now, the son's age is 8 and the man's age is 28.

\n" ); document.write( "12 years from now, the son's age will be 20 and the man's age will be 40. \n" ); document.write( "

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