document.write( "Question 1136563: Four years ago a man was 6times as old as his son.In twelve years time the man will be twice as old as his son.find their present ages.
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Algebra.Com's Answer #754336 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = the man's age now
\n" ); document.write( "Let \"+b+\" = his son's age
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\n" ); document.write( "(1) \"+a+-+4+=+6%2A%28+b+-+4+%29+\"
\n" ); document.write( "(2) \"+a+%2B+12+=+2%2A%28+b+%2B+12+%29+\"
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\n" ); document.write( "(1) \"+a+-+4+=+6b+-+24+\"
\n" ); document.write( "(1) \"+a+-+6b+=+-20+\"
\n" ); document.write( "(1) \"+-a+%2B+6b+=+20+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+a+%2B+12+=+2b%2B+24+\"
\n" ); document.write( "(2) \"+a+-+2b+=+12+\"
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\n" ); document.write( "Add (1) and (2)
\n" ); document.write( "(1) \"+-a+%2B+6b+=+20+\"
\n" ); document.write( "(2) \"+a+-+2b+=+12+\"
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\n" ); document.write( "\"+4b+=+32+\"
\n" ); document.write( "\"+b+=+8+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+a+-+2%2A8+=+12+\"
\n" ); document.write( "(2) \"+a+=+12+%2B+16+\"
\n" ); document.write( "(2) \"+a+=+28+\"
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\n" ); document.write( "The man is 28
\n" ); document.write( "The son is 8
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\n" ); document.write( "check:
\n" ); document.write( "4 yrs ago, the man was 24
\n" ); document.write( "4 yrs ago, son was 4
\n" ); document.write( "\"+4%2A6+=+24+\"
\n" ); document.write( "OK
\n" ); document.write( "and
\n" ); document.write( "In 12 yrs, man will be 40
\n" ); document.write( "In 12 yrs, son will be 20
\n" ); document.write( "\"+40+=+2%2A20+\"
\n" ); document.write( "OK\r
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