document.write( "Question 1136546: A person invested ​$7200 for 1​ year, part at 6​%, part at 10​%, and the remainder at 13​%.
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\n" ); document.write( "and 10​% combined. Find the amount invested at each rate.\r
\n" ); document.write( "\n" ); document.write( "The person invested $​[ ] at 6​%,
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Algebra.Com's Answer #754323 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1.  One part of the condition says that the total amount is $7200.\r\n" );
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document.write( "    The other part of the condition says that the amount invested at 13% is 200 more than the combined amount invested at 6% and 10%.\r\n" );
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document.write( "    It implies immediately via simple logic, that the combined amount invested at 6% and 10% is  \"%287200-200%29%2F2\" = 3500 dollars\r\n" );
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document.write( "    and the amount invested at 13% is  3500+200 = 3700 dollars.\r\n" );
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document.write( "2.  It implies that the interest produced by the amount at 13% is\r\n" );
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document.write( "        0.13*3700 = 481 dollars\r\n" );
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document.write( "    and the combined interest of two other accounts is  787 - 481 = 306 dollars.\r\n" );
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document.write( "3.  Let x be the amount invested at 10%.\r\n" );
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document.write( "    Then the amount invested at 6% is ((3500-x) dollars.\r\n" );
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document.write( "     The combined interest equation for these two accounts is\r\n" );
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document.write( "         0.10*x + 0.06*(3500-x) = 306.\r\n" );
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document.write( "     The solution to this equation is\r\n" );
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document.write( "         x = \"%28306+-+0.06%2A3500%29%2F%28010-0.06%29\" = 2400.\r\n" );
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document.write( "Answer.  $3700 invested at 13%;  $2400 invested at 10%,  and  (3500-2400) = 1100 dollars invested at 6%.\r\n" );
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document.write( "CHECK.   0.13*3700 + 0.10*2400 + 0.06*1100 = 787 dollars as the total interest.    ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "I'd like to make couple of comments to this solution.\r
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\n" ); document.write( "\n" ); document.write( "The method of solution was to reduce the problem from 3 unknowns to only two unknowns.\r
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\n" ); document.write( "\n" ); document.write( "Then the problem for two unknown investments was solved using single equation for only one unknown.\r
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\n" ); document.write( "\n" ); document.write( "The method of reducing such problems from 3 unknowns to only two is very well known.\r
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\n" ); document.write( "\n" ); document.write( "See the lesson \r
\n" ); document.write( "\n" ); document.write( "    - HOW TO algebreze and solve this problem on 2 equations in 2 unknowns \r
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\n" ); document.write( "\n" ); document.write( "On solution of investment problems for two accounts see the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Using systems of equations to solve problems on investment\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-I in this site\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Systems of two linear equations in two unknowns\".\r
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\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "If you think that I hid from you the reducing step from 3 unknowns to 2 unknowns,\r
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document.write( "    Let  A  be the amount invested at 13%  and  B  be  the combined amount invested ar 6% and 10%.\r\n" );
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document.write( "    We are given that \r\n" );
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document.write( "        A + B = 7200\r\n" );
document.write( "        A - B =  200\r\n" );
document.write( "  ----------------------   Add these two equations. You will get\r\n" );
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document.write( "      2A      = 7400  ==============>  A = 7400/2 = 3700  dollars.\r\n" );
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document.write( "     Then  B = 7200 - 3700 = 3500  dollars, exactly as I stated in the core text.\r\n" );
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document.write( "     Using logical arguments,  take off $200 from $7200 - then you will get a total of $7000, consisting of two equal parts \"reduced A\" and \"B\",\r\n" );
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document.write( "      so \"B\"  is 7000/2 = 3500 dollars and \"A\" is 3500+200 = 3700.\r\n" );
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