document.write( "Question 1136535: Mary is trying to put in a rectangular garden that is 5 feet longer than twice its width. She wants to have a sidewalk along two of the garden’s sides that is 3 feet wide. If the area of the sidewalk will be 213 ft2 ,help Mary find the dimensions of her garden. \n" ); document.write( "
Algebra.Com's Answer #754310 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "I will assume that the two side of the garden along which the sidewalk is to be put are two adjacent sides, rather than two opposite sides....

\n" ); document.write( "The width and length of the garden are x and 2x+5.

\n" ); document.write( "The lengths of the 3-foot-wide sidewalks are x and 2x+5 along those two sides.

\n" ); document.write( "And on the corner where the two sidewalks meet there will be a 3x3 square of sidewalk.

\n" ); document.write( "Then, since the total area of the sidewalk is 213 square feet,

\n" ); document.write( "\"3%28x%29%2B3%282x%2B5%29%2B3%283%29+=+213\"
\n" ); document.write( "\"3x+%2B+6x%2B15+%2B+9+=+213\"
\n" ); document.write( "\"9x+%2B+24+=+213\"
\n" ); document.write( "\"9x+=+189\"
\n" ); document.write( "\"x+=+21\"

\n" ); document.write( "The dimensions of her garden are x = 21 feet by (2x+5) = 47 feet.
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