document.write( "Question 1136533: A rectangular athletic field has a length that is 20 yards longer than its width. Its original width will be increased by 4 yds and its length will be decreased by 5 yds. The news field will have an area that is the same as the original field. Find the dimensions of the original field. \n" ); document.write( "
Algebra.Com's Answer #754299 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular athletic field has a length that is 20 yards longer than its width.
\n" ); document.write( " Its original width will be increased by 4 yds and its length will be decreased by 5 yds.
\n" ); document.write( " The new field will have an area that is the same as the original field.
\n" ); document.write( " Find the dimensions of the original field.
\n" ); document.write( "L = Length, W = width
\n" ); document.write( ":
\n" ); document.write( "L * W = (L-5)(W+4)
\n" ); document.write( "FOIL
\n" ); document.write( "LW = LW + 4L - 5w - 20
\n" ); document.write( "Subtract LW from both sides
\n" ); document.write( "0 = 4L - 5W - 20
\n" ); document.write( "\"field has a length that is 20 yards longer than its width.\"
\n" ); document.write( "0 = 4(W+20) - 5W - 20
\n" ); document.write( "0 = 4W + 80 - 5W - 20
\n" ); document.write( "0 = -W + 60
\n" ); document.write( "W = 60 yds is the width of the original field
\n" ); document.write( "and
\n" ); document.write( "60 + 20 = 80 yds is the length
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "check
\n" ); document.write( "60 * 80 = 4800
\n" ); document.write( "64 * 75 = 4800
\n" ); document.write( " \n" ); document.write( "
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