document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1136488>Question 1136488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At distance x from the base of a building, the angle of elevation to top of the building is 19 degrees.   The angle of elevation is 39 degrees if you walk 13 ft closer to the building.  There is a 10 ft antenna on top of the building.  Find the height from ground to the top of the antenna.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #754269 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=754269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If one draws this, tan 19=y/x and tan 39=y/(x-13), y being the building's height.<BR>\n" );
document.write( "x tan 19=x tan 39-13 tan 39<BR>\n" );
document.write( "x (tan19-tan 39)=-10.53<BR>\n" );
document.write( "x(-0.4655)=-10.53<BR>\n" );
document.write( "x=22.62'<BR>\n" );
document.write( "y=7.79'<BR>\n" );
document.write( "So the height to the top of the antenna is 17.79'<BR>\n" );
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