document.write( "Question 103607: how do i solve this problem?\r
\n" ); document.write( "\n" ); document.write( "Gigi's kids love honey-sweetened cerel. She mixes the hone-sweetened cereal with the unsweetened version of the same cereal. From experience, she knows that the misture is perfect whenthe amount of honey-sweetened cereal is exactly 40% of the mix. Her husband, Chase, has just mixed together a 14oz package of unsweetened cereal and a 32oz package of sweetened cereal. how much more unsweetened cereal does Gigi need to mix in to make th emix 40% sweetened and 60% unsweetened?\r
\n" ); document.write( "\n" ); document.write( "(i would show what i worked on, but i don't know how to start it and what to do.) \n" ); document.write( "
Algebra.Com's Answer #75422 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
From experience, she knows that the mixture is perfect when the amount of honey-sweetened cereal is exactly 40% of the mix. Her husband, Chase, has just mixed together a 14 oz package of unsweetened cereal and a 32 oz package of sweetened cereal. how much more unsweetened cereal does Gigi need to mix in to make the mix 40% sweetened and 60% unsweetened?
\n" ); document.write( ":
\n" ); document.write( "Dear student,
\n" ); document.write( "I made this problem unnecessarily complicated, think of it this way:
\n" ); document.write( "How much much unsweetened cereal will we have add to the original mixture to
\n" ); document.write( "get 40%?
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\n" ); document.write( "Original mixture amt: 14 + 32 = 46 oz
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\n" ); document.write( "We have to add the amt that will make 32 oz equal to 40% of the final mixture.
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of unsweetened cereal to be added
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\n" ); document.write( "32 = .40(46 + x)
\n" ); document.write( ":
\n" ); document.write( "32 = 18.4 + .4x
\n" ); document.write( ":
\n" ); document.write( "32 - 18.4 = .4x
\n" ); document.write( ":
\n" ); document.write( "13.6 = .4x
\n" ); document.write( ":
\n" ); document.write( "x = 13.6/.4
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\n" ); document.write( "x = 34 oz of unsweetened cereal required
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\n" ); document.write( "Check our solution:
\n" ); document.write( "Total amt after adding the unsweetened stuff: 34 + 46 = 80 oz
\n" ); document.write( "sweet cereal percentage: 32/80 = .4; which is 40% as required
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\n" ); document.write( "Did this make MORE sense to you now? \n" ); document.write( "
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