document.write( "Question 1136353: The half-life of Palladium-100 is 4 days. After 20 days a sample of Palladium-100 has been reduced to a mass of 5 mg.
\n" ); document.write( "What was the initial mass (in mg) of the sample?
\n" ); document.write( "What is the mass 4 weeks after the start? \n" ); document.write( "

Algebra.Com's Answer #754118 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Scientists like to write exponential decay functions using base e; and sometimes there are good reasons for that. But with half life problems, it seems to me far easier to write the exponential decay function as

\n" ); document.write( "A = I(1./2)^t

\n" ); document.write( "where t is the number of half lives.

\n" ); document.write( "In this problem, the half life is 4 days, and the stated period is 20 days. That is an integer number of half lives; the solution is simple.

\n" ); document.write( "20 days if 5 half lives; the original mass has been reduced by a factor of 2^5=32. If 5g are left, the original amount was 5*32 = 160g.

\n" ); document.write( "Note the other tutor, using e and natural logarithms, ended up with the wrong answer by transposing a couple of digits near the end of the calculations.

\n" ); document.write( "The amount remaining after 4 weeks = 28 days = 7 half lives is the original 160g, reduced by a factor of 2^7 = 128 (or the amount remaining after 20 days, reduced by another factor of 2^2=4 for the 2 additional half lives). That amount is 160/128 = 5/4 = 1.25g. \n" ); document.write( "

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