document.write( "Question 1136330: Find the equation in standard form of the hyperbola that has foci at (8, 1)(-8, 1) and
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Algebra.Com's Answer #754116 by MathLover1(20850)\"\" \"About 
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Find the equation in standard form of the hyperbola that has \r
\n" ); document.write( "\n" ); document.write( "foci at (\"8\", \"1\") , (\"-8\", \"1\")
\n" ); document.write( "and transverse axis with length \"14\" \r
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\n" ); document.write( "\n" ); document.write( "The standard form of a hyperbola that opens sideways is \r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+h%29%5E2+%2F+a%5E2+-+%28y+-+k%29%5E2+%2F+b%5E2+=+1\"\r
\n" ); document.write( "\n" ); document.write( "For the hyperbola that opens up and down, it is \r
\n" ); document.write( "\n" ); document.write( "\"%28y+-+k%29%5E2+%2F+a%5E2+-+%28x+-+h%29%5E2+%2F+b%5E2+=+1\"\r
\n" ); document.write( "\n" ); document.write( " In both cases, the center of the hyperbola is given by (\"h\", \"k\").
\n" ); document.write( "The vertices are \"a+\"spaces away from the center.
\n" ); document.write( "The \"foci\" of an hyperbola are \"inside\" each branch, and each focus is located some fixed distance \"c\" from the center.
\n" ); document.write( "The endpoints of the transverse axis are called the vertices of the hyperbola.
\n" ); document.write( "The distance between the vertices is \"2a\". The distance between the foci is \"2c\".\r
\n" ); document.write( "\n" ); document.write( "if foci at (\"8\", \"1\") , (\"-8\", \"1\") , the distance between is \"16\", then\r
\n" ); document.write( "\n" ); document.write( "\"2c=16\" \r
\n" ); document.write( "\n" ); document.write( "\"c=8\"\r
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\n" ); document.write( "\n" ); document.write( "if transverse axis with length \"14\", means distance between vertices is \r
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\n" ); document.write( "\n" ); document.write( "\"2a=14\"->\"a=7\"\r
\n" ); document.write( "\n" ); document.write( "and vertices are at (\"7\", \"0\") , (\"-7\", \"0\")
\n" ); document.write( "and its midpoint is the center of the hyperbola => which is at (\"-7\", \"0\")\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+0%29%5E2+%2F+7%5E2+-+%28y+-+0%29%5E2+%2F+b%5E2+=+1\"\r
\n" ); document.write( "\n" ); document.write( "find \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=c%5E2-a%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=8%5E2-7%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=64-49\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=15\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2F+49+-+y%5E2+%2F15+=+1\"\r
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