document.write( "Question 1136341: The angle’s measure is 60 degrees more than triple that of its supplement. Fine this angle. \n" ); document.write( "

Algebra.Com's Answer #754104 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "supplementary angles are two angles whose sum is $\"180\"$ °\r
\n" ); document.write( "\n" ); document.write( "let one angle be $\"alpha\"$ and its supplement $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( "so, $\"alpha%2Bbeta=180\"$ ° ........eq.1\r
\n" ); document.write( "\n" ); document.write( "if measure of $\"alpha\"$ is $\"60\"$ ° more than $\"triple\"$ that of its supplement $\"beta\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=3beta%2B60\"$ °........substitute in eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"3beta%2B60%2Bbeta=180\"$ ° .........solve for $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4beta=180-60\"$ ° \r
\n" ); document.write( "\n" ); document.write( " $\"4beta=120\"$ ° \r
\n" ); document.write( "\n" ); document.write( " $\"beta=120%2F4\"$ ° \r
\n" ); document.write( "\n" ); document.write( " $\"beta=30\"$ ° \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "find $\"alpha\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"alpha=3beta%2B60\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=3%2A30%2B60\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=150\"$ °\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );