document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=961922>Question 961922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Laura owns and operates Aunt Linda's Pecan pies. She has learned that her profits, p(x), from the sale of x cases of pies ,are given by p(x)=150x-x^2.<BR>\n" );
document.write( "a, The company will \"break-even\" when the profit is zero. How many cases of pies should Laura sell in order to break-even? (solve for x when p(x)=0).<BR>\n" );
document.write( "b, how many cases of pies should she sell in order to maximize her profit?<BR>\n" );
document.write( "c, what is the maximum profit? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #754027 by </B><A HREF=/tutors/aboutme.mpl?userid=steffy67248><B>steffy67248(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=steffy67248><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=754027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A)150<BR>\n" );
document.write( "B)-x^2-150x....Put this into the formula (-b/2a)....so it'll become (-150/2(-1))...you get 75<BR>\n" );
document.write( "C) Plug in what you got for part \"B\" into the equation.....so it'll be <BR>\n" );
document.write( "150(75)-(75)^2...which is equal to 5625\r<BR>\n" );
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