document.write( "Question 1136238: In 2005, 74% of all airline flights were on-time. If we choose a simple random sample of 2000 flights, find the probability that (be as accurate as the proper process allows)
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document.write( "(a) at least 77% of the sample's flights were on time:
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document.write( "(b) at most 1420 of the sample's flights were on time: \n" );
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Algebra.Com's Answer #754008 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z value is (0.77-0.74)/sqrt(0.74*0.26/2000) \n" ); document.write( "z>3.06 p=0.0022\r \n" ); document.write( "\n" ); document.write( "1420 is 0.71 \n" ); document.write( "this is the same probability \n" ); document.write( "z<-3.06 \n" ); document.write( " |