document.write( "Question 1136210: The amount of copper ore produced from a copper mine in Arizona is modeled by the function f(t)=200+32t, where t is the numbers of years since 2005 and f(t) is measured in thousands of tons.\r
\n" ); document.write( "\n" ); document.write( "A. What is the slope of the graph? P.S I think maybe it is 32 but I'm not sure\r
\n" ); document.write( "\n" ); document.write( "B. At what rate is the amount of ore produced changing?(Be specfic include units)\r
\n" ); document.write( "\n" ); document.write( "C. How much ore had been mined by the year 2005?(Be specfic include units)
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Algebra.Com's Answer #753999 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
All the units in the equation have to be consistent, so
\n" ); document.write( "the terms must look like:
\n" ); document.write( "[ thousands of tons ] = [ thousands of tons ] + [ thousands of tons ]
\n" ); document.write( "The constant term just shifts the graph up or down ( up in this case )
\n" ); document.write( "and has no effect on the slope
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\n" ); document.write( "(a)
\n" ); document.write( "The units of the \"+32t+\" are broken down like this:
\n" ); document.write( "[ thousands of tons ] = [ ( thousands of tons / year ) x ( years ) ]
\n" ); document.write( "This is [ slope ] x [ time ], so the slope is \"+32+\"
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\n" ); document.write( "(b)
\n" ); document.write( "32 thousand tons / year
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\n" ); document.write( "The year 2005 is \"+t+=+0+\" on the graph, so
\n" ); document.write( "\"+f%28t%29+=+200+%2B+32%2A0+\"
\n" ); document.write( "\"+f%28t%29+=+200+\"
\n" ); document.write( "200 thousand tons were mined by 2005
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\n" ); document.write( "Here's the graph:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-1%2C+10%2C+-100%2C+600%2C+200+%2B+32x+%29+\"
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