document.write( "Question 1136231: Prove that (sin³A + cos³A)/(sinA + cosA) + (sin³A - cos³A)/(sinA - cosA) = 2 \n" ); document.write( "
Algebra.Com's Answer #753998 by MathLover1(20849)\"\" \"About 
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Prove that \r
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\n" ); document.write( "\n" ); document.write( "use Factoring a Sum of Cubes rule:\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E3+%2B+b%5E3+=+%28a+%2B+b%29%28a%5E2+-+ab+%2B+b%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin%5E2%28A%29+%2B+cos%5E2%28A%29+%2B+sin%5E2%28A%29+%2B+cos%5E2%28A%29+=+2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28sin%5E2%28A%29+%2B+cos%5E2%28A%29%29+=+2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%281%29+=+2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"2++=+2+\"\r
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