document.write( "Question 103744: tom and tina set out on their bikes at noon and travel toward each other, meeting at 2:30PM. Tina's speed is 4 mi/hr faster than tom's speed and their starting points are 50 mi. apart \n" ); document.write( "
Algebra.Com's Answer #75397 by oberobic(2304)\"\" \"About 
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Distance = Rate * Time
\n" ); document.write( "In this case we know:
\n" ); document.write( "Tom's rate is 4 mph slower than Tina. Call these x and x+4, respectively.
\n" ); document.write( "We know they traveled for 2 hr 30 min, which is 2.5 hr.
\n" ); document.write( "So Tom traveled 2.5x, and Tina traveled 2.5(x+4)=2.5x+10.
\n" ); document.write( "We know that at noon they had covered 50 miles in total, part of which was traveled by Tom and part of which was traveled by Tina.
\n" ); document.write( "So we know that 2.5x (the distance Tom traveled) + 2.5x + 10 (the distance Tina traveled) = 50.
\n" ); document.write( "2.5x + 2.5x + 10 = 50
\n" ); document.write( "Combining:
\n" ); document.write( "5x + 10 = 50
\n" ); document.write( "Subract 10 from both sides:
\n" ); document.write( "5x = 40
\n" ); document.write( "Divide through by 5:
\n" ); document.write( "x = 8
\n" ); document.write( "So Tom's speed is 8 mph.
\n" ); document.write( "Tina's speed is 4 mph faster, so it is 8+4 = 12 mph.
\n" ); document.write( "ALWAYS check!
\n" ); document.write( "In this case, substitute the speeds to ensure they covered 50 miles.
\n" ); document.write( "2.5*8 = 20 = Tom's distance traveled.
\n" ); document.write( "2.5*12 = 30 = Tina's distance traveled.
\n" ); document.write( "Check! \n" ); document.write( "
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