document.write( "Question 1136134: A three-digit number is 13 times the product of its digits. The hundreds digit is
\n" ); document.write( "larger than either of the other two digits. What is this number?
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Algebra.Com's Answer #753898 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Since the three-digit number is equal to \"13\" times the product of its digits, it is divisible by its \"hundreds\" digit, which is the largest of the three. \r
\n" ); document.write( "\n" ); document.write( "If we increase both the tens digit and the units digit to the hundreds digit, the quotient will be \"111\". If instead we decrease both of them to \"0\", the quotient will be \"100\".\r
\n" ); document.write( "\n" ); document.write( "The actual quotient is between \"100\" and \"111\", and since it is divisible by \"13\", it must be \"104\".
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\n" ); document.write( "The product of the tens digit and the units digit is \"104%2F+13=8\".\r
\n" ); document.write( "\n" ); document.write( "Since\"+8=2+%2A+4=1%2A+8\", the three-digit number is one of \"624\", \"642\", \"918\" and \"981\".\r
\n" ); document.write( "\n" ); document.write( "The \"only\"\"+one\" divisible by \"13\" is \"13%2A6%2A+2%2A4=+624\". \r
\n" ); document.write( "\n" ); document.write( "answer:The number is \"624\"\r
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