document.write( "Question 1136030: Phyllis invested 43000dollars, a portion earning a simple interest rate of 5
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document.write( "percent per year and the rest earning a rate of 7
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document.write( "percent per year. After one year the total interest earned on these investments was 2430 dollars. How much money did she invest at each rate?\r
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document.write( "At rate 5percent :
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document.write( "At rate 7percent : \n" );
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Algebra.Com's Answer #753776 by ikleyn(52810)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " I will show you two methods of solving this problem.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solution 1. Using the system of 2 equations\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let x be the amount invested at 5% and y be the amount invested at 7%.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then you have these two equations\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x + y = 43000 dollars (1) (the sum of amounts is equal to the total investment)\r\n" ); document.write( "\r\n" ); document.write( " 0.05x + 0.07y = 2430 dollars (2) (the sum of interests is equal to the total interest)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "I will apply the Substitution method to solve the system.\r\n" ); document.write( "For it, I express\r\n" ); document.write( "\r\n" ); document.write( " x = 43000 - y (3)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "from the first equation and then substitute it into the second equation, replacing x. I will get\r\n" ); document.write( "\r\n" ); document.write( " 0.05*(43000 - y) + 0.07y = 2430. (4)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and solve this equation step by step:\r\n" ); document.write( "\r\n" ); document.write( " 0.05*43000 - 0.05y + 0.07y = 2430\r\n" ); document.write( "\r\n" ); document.write( " 0.07y - 0.05y = 2430 - 0.05*43000\r\n" ); document.write( "\r\n" ); document.write( " 0.02y = 280\r\n" ); document.write( "\r\n" ); document.write( " y =\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solution 2. Using single equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let y be the amount invested at 7%.\r\n" ); document.write( "\r\n" ); document.write( "Then the amount invested at 5% is the rest (43000-y) dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The 5% investment gives the interest of 0.05*(43000-y) dollars.\r\n" ); document.write( "\r\n" ); document.write( "The 7% investment gives the interest of 0.07*y dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "In total, these two investments give $2430. Therefore, the \"interest\" equation is\r\n" ); document.write( "\r\n" ); document.write( " 0.05*(43000-y) + 0.07*y = 2430.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It is the same equation (4) as you obtained in the Solution 1 after substitution.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, the solution of this equation is the same, and it produces the same answer.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "My solutions and explanations are completed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You learned two methods setuping the equations along with the methods of their solutions.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " H a p p y l e a r n i n g !\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is a standard and typical problem on investments.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more details, or if you want to see other similar problems solved by different methods, look into the lesson \r \n" ); document.write( "\n" ); document.write( " - Using systems of equations to solve problems on investment\r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You will find there different approaches (using one equation or a system of two equations in two unknowns), as well as \n" ); document.write( "different methods of solution to the equations (Substitution, Elimination).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r \n" ); document.write( "\n" ); document.write( " - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic \"Systems of two linear equations in two unknowns\".\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I \n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |