document.write( "Question 1136015: The perimeter of a rectangle is 64 cm. The length is 4 cm less than twice the width. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #753769 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is:\"P=2%28L%2BW%29\"\r
\n" ); document.write( "\n" ); document.write( "given: \"P=64cm\"\r
\n" ); document.write( "\n" ); document.write( "=>\"2%28L%2BW%29=64cm\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "the length is \"4cm\" less than \"twice\" the width:\r
\n" ); document.write( "\n" ); document.write( "\"L=2W-4cm\"...eq.2...substitute in eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"2%282W-4cm%2BW%29=64cm\"....eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"4W-8cm%2B2W=64cm\"\r
\n" ); document.write( "\n" ); document.write( "\"6W=64cm%2B8cm\"\r
\n" ); document.write( "\n" ); document.write( "\"6W=72cm\"\r
\n" ); document.write( "\n" ); document.write( "\"W=72cm%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"W=12cm\"\r
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\n" ); document.write( "\n" ); document.write( "go to eq.2\r
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\n" ); document.write( "\n" ); document.write( "\"L=2W-4cm\"...eq.2...plug in \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"L=2%2A12cm-4cm\"\r
\n" ); document.write( "\n" ); document.write( "\"L=24cm-4cm\"\r
\n" ); document.write( "\n" ); document.write( "\"L=20cm\"\r
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