document.write( "Question 1135977: Find the vertex, focus, directrix, and focal width of the parabola.
\n" ); document.write( "x = 10y2
\n" ); document.write( "choices are below
\n" ); document.write( "Vertex: (0, 0); Focus: one divided by forty comma zero ; Directrix: x = negative one divided by forty ; Focal width: 0.1
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\n" ); document.write( "Vertex: (0, 0); Focus: one divided by ten comma zero ; Directrix: x = negative one divided by ten ; Focal width: 0.1
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\n" ); document.write( "Vertex: (0, 0); Focus: one divided by forty comma zero ; Directrix: x = one divided by forty ; Focal width: 40
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\n" ); document.write( "Vertex: (0, 0); Focus: zero comma one divided by forty ; Directrix: y = negative one divided by forty ; Focal width: 40
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Algebra.Com's Answer #753753 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "For me, the most useful form of the equation of a parabola (that opens right or left) is

\n" ); document.write( "\"x-h+=+%281%2F%284p%29%29%28y-k%29%5E2\"

\n" ); document.write( "In this form...
\n" ); document.write( "(1) the vertex is (h,k);
\n" ); document.write( "(2) p is the (directed) distance from the vertex to the focus; which means -p is the directed distance from the vertex to the directrix; and
\n" ); document.write( "(3) 4p is the focal width (length of the latus rectum)

\n" ); document.write( "Written in that form, the equation in your example is

\n" ); document.write( "\"x-0+=+%281%2F%281%2F10%29%29%28y-0%29%5E2\"

\n" ); document.write( "So...
\n" ); document.write( "(1) the vertex is (0,0);
\n" ); document.write( "(2) 4p=1/10 so p=1/40, so the focus is (1/40,0) and the directrix is x = -1/40; and
\n" ); document.write( "(3) the focal width is 4p = 1/10 = 0.1

\n" ); document.write( "The first answer choice is the correct one.
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