document.write( "Question 1135977: Find the vertex, focus, directrix, and focal width of the parabola.
\n" ); document.write( "x = 10y2
\n" ); document.write( "choices are below
\n" ); document.write( "Vertex: (0, 0); Focus: one divided by forty comma zero ; Directrix: x = negative one divided by forty ; Focal width: 0.1
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\n" ); document.write( "Vertex: (0, 0); Focus: one divided by ten comma zero ; Directrix: x = negative one divided by ten ; Focal width: 0.1
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\n" ); document.write( "Vertex: (0, 0); Focus: one divided by forty comma zero ; Directrix: x = one divided by forty ; Focal width: 40
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\n" ); document.write( "Vertex: (0, 0); Focus: zero comma one divided by forty ; Directrix: y = negative one divided by forty ; Focal width: 40
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Algebra.Com's Answer #753729 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"4p%28x-h%29=%28y-k%29%5E2\" is the standard equation for a right-left facing parabola with vertex at (\"h\", \"k\" )\r
\n" ); document.write( "\n" ); document.write( "rewrite \"x=10y%5E2\" in the standard form :\r
\n" ); document.write( "\n" ); document.write( "\"x=10y%5E2\".........both sides divide by \"10\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2F10=10y%5E2%2F10\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2F10=y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "factor \"4\"\r
\n" ); document.write( "\n" ); document.write( "\"4%28%281%2F10%29%2F4%29x=y%5E2\"....simplify\r
\n" ); document.write( "\n" ); document.write( "\"4%281%2F40%29x=y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "rewrite as
\n" ); document.write( " \"4%281%2F40%29%28x-0%29=%28y-0%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "so, (\"h\",\"+k\" )= (\"0\", \"0\" ), \"p=+1%2F40+\"\r
\n" ); document.write( "\n" ); document.write( "parabola is symmetric around the x-axis and so the focus lies a distance \"p\" from the center (\"0\", \"0\") along the x-axis \r
\n" ); document.write( "\n" ); document.write( "(\"0%2Bp\",\"0\")
\n" ); document.write( "(\"0%2B1%2F40\",\"0\")
\n" ); document.write( "(\"1%2F40\",\"0\")->focus\r
\n" ); document.write( "\n" ); document.write( "the distance between the focus and directrix is \"p=+1%2F40+\"\r
\n" ); document.write( "\n" ); document.write( "parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance -p from the center left (\"0\",\"0\") x-coordinate \r
\n" ); document.write( "\n" ); document.write( "\"x=0-p\"
\n" ); document.write( "\"x=0-1%2F40\"
\n" ); document.write( "\"x=-1%2F40\"\r
\n" ); document.write( "\n" ); document.write( "so, you have:
\n" ); document.write( "vertex at (\"0\", \"0\" ),
\n" ); document.write( "focus at (\"1%2F40\",\"0\")
\n" ); document.write( "directrix is \"x=-1%2F40\"\r
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\n" ); document.write( "\n" ); document.write( "you can use only this one of your choices as an answer \r
\n" ); document.write( "\n" ); document.write( "Vertex: (\"0\", \"0\");
\n" ); document.write( "Focus: (\"1%2F40\",\"0\");
\n" ); document.write( "Directrix: x = 1/40; -> this is incorrect, should be \"highlight%28x=-1%2F40%29\"
\n" ); document.write( "Focal width: \"40\"\r
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