document.write( "Question 1135956: two watches are set at 9: am one watch runs 2 min fast every hour. the other watch runs 1 min slow every hour. the faster watch will ahead one hour the slower watch at what time the next morning. \n" ); document.write( "
Algebra.Com's Answer #753679 by josmiceli(19441)\"\" \"About 
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Let \"+n+\" = the number of minutes that go by
\n" ); document.write( "\"+n%2A%28+1+%2B+2+%2F60+%29+\" = what the fast clock
\n" ); document.write( "shows after \"+n+\" min
\n" ); document.write( "\"+n%2A%28+1+-+1%2F60+%29+\" = what the slow clock
\n" ); document.write( "shows after \"+n+\" min
\n" ); document.write( "-------------------------------
\n" ); document.write( "When is the difference in the clocks 1 hr?
\n" ); document.write( "\"+n%2A%28+1+%2B+2%2F60+%29+-+n%2A%28+1+-+1%2F60+%29+=+60+\"
\n" ); document.write( "\"+n%2A%28+1+%2B+2%2F60+-+1+%2B+1%2F60+%29+=+60+\"
\n" ); document.write( "\"+n%2A%28+3%2F60+%29+=+60+\"
\n" ); document.write( "\"+n+=+3600%2F3+\"
\n" ); document.write( "\"+n+=+1200+\" min
\n" ); document.write( "Convert 1200 min to hrs
\n" ); document.write( "\"+1200%2F60+=+20+\" hrs
\n" ); document.write( "9 AM plus 12 hrs is 9 PM
\n" ); document.write( "9 PM plus 8 hrs is 5 AM
\n" ); document.write( "5 AM the next morning
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