document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135953>Question 1135953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5. (8 pts)<BR>\n" );
document.write( "(a) log3 1 =_______ (fill in the blank)<BR>\n" );
document.write( "(b) Let 𝑥 = log3 1/243 State the exponential form of the equation. <BR>\n" );
document.write( "(c) Determine the numerical value of log3 1/243 , in simplest form. Work optional </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753675 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^0=1, so the answer is 0.<BR>\n" );
document.write( "1/243 is 3^(-5); 3^x=1/243, so x=-5<BR>\n" );
document.write( "log 3 (1/243)=-5\r<BR>\n" );
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document.write( "it is also log 3 (1)- log (3) 243), which is 0-5 or -5.<BR>\n" );
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