document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135941>Question 1135941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x=√5+√3 then the value of x-1/x will be<BR>\n" );
document.write( "0.5(√5+3√3)<BR>\n" );
document.write( "0.5(3√5+2√3)<BR>\n" );
document.write( "None </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753669 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is the same as (x^2-1)/x<BR>\n" );
document.write( "That is 5+3+2 sqrt(15)-1 divided by sqrt (5) +sqrt (3)<BR>\n" );
document.write( "multiply (7+2 sqrt(15) by the conjugate of the denominator sqrt(5)- sqrt(3).  Multiply the denominator by the conjugate.\r<BR>\n" );
document.write( "\n" );
document.write( "This will yield 7 sqrt(5)-7 sqrt(3)+10 sqrt(3)-2 sqrt (45) divided by 2<BR>\n" );
document.write( "The numerator simplifies to 3 sqrt(3)+ sqrt(5)<BR>\n" );
document.write( "The denominator is 2<BR>\n" );
document.write( "the answer is 0.5 (sqrt (5)+3 sqrt (3)) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );