document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135939>Question 1135939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 216^-2k<BR>\n" );
document.write( "-------- = 36   Please show steps and solution.<BR>\n" );
document.write( "36^-2k-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753653 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> well, .....\r<BR>\n" );
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document.write( "i got k = 2 and it appears to be correct.\r<BR>\n" );
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document.write( "here's my worksheet.\r<BR>\n" );
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document.write( "in step 1 i copied the problem.\r<BR>\n" );
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document.write( "in step 2 i multiplied both sides of the equation by 36^(-2k-3)\r<BR>\n" );
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document.write( "in step 3 i converted 36^(-2k-3) to 36^(-2k) / 36^3 because they're equivalent.\r<BR>\n" );
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document.write( "in step 4 i divided 36 in the numerator into 36^3 in the denominator to get 36^2 in the denominator.\r<BR>\n" );
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document.write( "in step 5 i replaced (6 * 36)^(-2k) with 6^(-2k) * 36^(-2k) because they're equivalent.\r<BR>\n" );
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document.write( "in step 6 i divided both sides of the equation by 36^(-2k) which then removed 36^(-2k) from the equation because 36^(-2k) / 36^(-2k) = 1.\r<BR>\n" );
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document.write( "in step 7 i made 6^(-2k) equal to 1 / 6^(2k) because they're equivalent.\r<BR>\n" );
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document.write( "in step 8 i cross multiplied.\r<BR>\n" );
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document.write( "in step 9 i took the log of both sides of the equation to get log(36^2)( = log(6^(2k)) which then became 2 * log(36) = 2k * log(6) because log(x^a) = a*log(x).\r<BR>\n" );
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document.write( "in step 10 i divided both sides of the equation by log(6).\r<BR>\n" );
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document.write( "in step 11 i divided both sides of the equation by 2.\r<BR>\n" );
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document.write( "in step 12 i solved for k.\r<BR>\n" );
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document.write( "any questions how or why i got what i got, send email to dtheophilis@gmail.com.\r<BR>\n" );
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document.write( "in donfirmed by replacing k with 2 in the original equation and evaluated it to get 36 = 36.\r<BR>\n" );
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