document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135940>Question 1135940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One hose can fill a small swimming pool in 90 minutes. A larger hose can fill the pool in 30 minutes. How long will it take the two hoses to fill the pool working together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753651 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in x minutes, the first hose will fill x/90 of the pool and the larger will fill x/30<BR>\n" );
document.write( "they will both fill the pool when x/90 + x/30=1<BR>\n" );
document.write( "multiply by LCD 90 and x+3x=90<BR>\n" );
document.write( "4x=90<BR>\n" );
document.write( "x=22.25 minutes  ANSWER\r<BR>\n" );
document.write( "\n" );
document.write( "check<BR>\n" );
document.write( "22.5/90 + 22.5/30=1, and the larger hose will do 3/4 of the filling. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );