document.write( "Question 1135889: Solve this equation; find two values for t (II and III quadrant)
\n" ); document.write( "70=55-23cos\"%282pi%2F365%29\"(t-30)\r
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\n" ); document.write( "\n" ); document.write( "I've tried to work this out for about an hour, but I keep getting different answers. Any help would be greatly appreciated. Thank you in advance!
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Algebra.Com's Answer #753595 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "\"70+=+55-23cos%28%282pi%2F365%29%28t-30%29%29\"

\n" ); document.write( "\"15+=+-23cos%28%282pi%2F365%29%28t-30%29%29\"

\n" ); document.write( "\"cos%28%282pi%2F365%29%28t-30%29%29+=+-15%2F23\"

\n" ); document.write( "\"%28%282pi%2F365%29%28t-30%29%29+=+arccos%28-15%2F23%29\" = 2.281245 (radians) to several decimal places

\n" ); document.write( "\"t-30+=+2.281245%2A%28365%2F%282pi%29%29+=+132.52106\" degrees
\n" ); document.write( "\"t+=+162.52106\" degrees

\n" ); document.write( "That's the answer in degrees for the angle in quadrant II.

\n" ); document.write( "For the angle in quadrant III...

\n" ); document.write( "\"%28%282pi%2F365%29%28t-30%29%29+=+2pi+-+arccos%28-15%2F23%29\" = 4.00194 (radians)

\n" ); document.write( "\"t-30+=+4.00194%2A%28365%2F%282pi%29%29+=+232.4789\" degrees

\n" ); document.write( "\"t+=+262.4789\" degrees

\n" ); document.write( "ANSWERS (degrees): 162.52106; 262.4789
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