document.write( "Question 103632: x^2+y^2=6y sketch the graph of the equation. This is one of the questions that are difficult for me \n" ); document.write( "
Algebra.Com's Answer #75353 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! x^2+y^2=6y \n" ); document.write( "Best bet is to complete the square for y and see where we are then. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Completing the square for y: \n" ); document.write( "(y+A)^2=y^2+2A+A^2 \n" ); document.write( "If I compare terms in your equation and this equation, I see that: \n" ); document.write( "2Ay=-6y \n" ); document.write( "2A=-6 \n" ); document.write( "A=-3 \n" ); document.write( "Once I know A, then \n" ); document.write( "A^2 = 9 \n" ); document.write( "If I add 9 to both sides of the equation, I get:0 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK. If you compare this equation with the equation of a circle of radius, R, centered at (h,k): \n" ); document.write( " \n" ); document.write( "You get \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Your equation is a circle centered at (0,3) with a radius of 3. \n" ); document.write( " |