document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135842>Question 1135842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three terms of an A.P. is 21 and the product of the first and third exceeds the second term by 6, find the terms.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753525 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a1+a2+a3=21<BR>\n" );
document.write( "note, a2 is n more than a1 and a3 is n more than a2 so the sum is 3a2=21 and a2=7\r<BR>\n" );
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document.write( "a1*a3=a2+6<BR>\n" );
document.write( "so a1*a3=13\r<BR>\n" );
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document.write( "a2-a1=a3-a2\r<BR>\n" );
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document.write( "a1=1<BR>\n" );
document.write( "a2=7<BR>\n" );
document.write( "a3=13\r<BR>\n" );
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