document.write( "Question 1135823: Can you answer this question for me please it would be nice thanks again
\n" ); document.write( "log base 6(X+1)
\n" ); document.write( "What it says that it is log with a base of 6 times (x+1)
\n" ); document.write( "I would like to know how to put it into exponential formula!
\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #753501 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
You should make sure you know how to read
\n" ); document.write( "this expression. In a more simple form:
\n" ); document.write( " $\"+log%28+a%2C+b+%29+=+c+\"$
\n" ); document.write( "The left side says that the right side is a log
\n" ); document.write( "which is an exponent.
\n" ); document.write( "The base is $\"+a+\"$ which is what is raised to
\n" ); document.write( "the power $\"+c+\"$
\n" ); document.write( "The result of $\"+a%5Ec+\"$ is $\"+b+\"$
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\n" ); document.write( "Using your expression, I'll make it an equation:
\n" ); document.write( " $\"+log%28+6%2C+x%2B1+%29+=+c+\"$
\n" ); document.write( "Following the above example:
\n" ); document.write( " $\"+6%5Ec+=+x%2B1+\"$
\n" ); document.write( "If you can't use the $\"+c+\"$ , then the way to
\n" ); document.write( "express it is:
\n" ); document.write( " $\"+6%5E%28%28+log%28+6%2C+x%2B1+%29+%29%29+=+x+%2B+1+\"$ \r
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