document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135820>Question 1135820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Working together, it takes two different sized hoses <BR>\n" );
document.write( " 30 minutes to fill a small swimming pool. If it takes <BR>\n" );
document.write( "45 minutes for the larger hose to fill the swimming pool by itself, how long will it take the smaller hose to fill the pool on its own? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753500 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the standard algebraic method for solving \"working together\" problems like this that I find many students prefer.<br><BR>\n" );
document.write( "(1) Find the least common multiple of the given times.<BR>\n" );
document.write( "The LCM of 30 and 45 is 90.<br><BR>\n" );
document.write( "(2) Determine how many times each hose could fill the pool in that amount of time.<BR>\n" );
document.write( "The two hoses together could fill the pool 90/30 = 3 times.<BR>\n" );
document.write( "The larger hose could fill the pool 90/45 = 2 times.<br><BR>\n" );
document.write( "The large hose alone could fill the pool 2 times in 90 minutes; the two together could fill the pool 3 times.  That means that in 90 minutes the smaller hose could fill the pool once.<br><BR>\n" );
document.write( "So the time it takes the smaller hose to fill the pool is 90 minutes. </SPAN>\n" );
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