document.write( "Question 103611: Mark is 10 years younger than Larry. Larry's age in 8 years will exceed twice Mark's age 3 years ago by 4 years. How old is each now?\r
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Algebra.Com's Answer #75348 by Earlsdon(6294)\"\" \"About 
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Let M = Mark's present age and L = Larry's present age.
\n" ); document.write( "From the problem description, you can write:
\n" ); document.write( "M = L-10 \"Mark is 10 years younger than Larry\"
\n" ); document.write( "(L+8) = 2(M-3)+4 \"Larry's age in 8 years (L+8) will exceed twice Mark's age 3 years ago (2(M-3)) by 4 years (+4). Putting it all together, you have:
\n" ); document.write( "1) M = L-10 and
\n" ); document.write( "2) L+8 = 2(M-3)+4 Substitute the M from equation 1) here and solve for L.\r
\n" ); document.write( "\n" ); document.write( "L+8 = 2((L-10)-3)+4 Simplify and solve for L
\n" ); document.write( "L+8 = 2(L-13)+4
\n" ); document.write( "L+8 = 2L-26+4
\n" ); document.write( "L+8 = 2L-22 Subtract L from both sides.
\n" ); document.write( "8 = L-22 Add 22 to both sides.
\n" ); document.write( "30 = L
\n" ); document.write( "Larry's present age is 30
\n" ); document.write( "M = L-10
\n" ); document.write( "M = 30-10
\n" ); document.write( "M = 20
\n" ); document.write( "Mark's present age is 20\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "M = L-10
\n" ); document.write( "20 = 30-10
\n" ); document.write( "20 = 20 OK!
\n" ); document.write( "L+8 = 2(M-3)+4
\n" ); document.write( "30+8 = 2(20-3)+4
\n" ); document.write( "38 = 2(17)+4
\n" ); document.write( "38 = 34+4
\n" ); document.write( "38 = 38 OK! \n" ); document.write( "
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