document.write( "Question 1135782: Evaluate the piecewise function at the given value of the independent variable.\r
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\n" ); document.write( "\n" ); document.write( "f(x)= -5x-2 if <4\r
\n" ); document.write( "\n" ); document.write( " -2x-4 if > 4 Determinre f(7)
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Algebra.Com's Answer #753464 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Answer: -18\r
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\n" ); document.write( "How I got that answer:\r
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\n" ); document.write( "\n" ); document.write( "The piece wise function f(x) has a dual identity so to speak. It is either \"f%28x%29+=+-5x-2\" OR \"f%28x%29+=+-2x-4\". It depends on what the x value is. Note: f(x) cannot be both at the same time. \r
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\n" ); document.write( "\n" ); document.write( "If \"x+%3C+4\", then \"f%28x%29+=+-5x-2\" as the first line shows in the piecewise function.
\n" ); document.write( "OR
\n" ); document.write( "If \"x+%3E=+4\", then \"f%28x%29+=+-2x-4\" as the second line shows in the piecewise function.\r
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\n" ); document.write( "\n" ); document.write( "The value x = 7 makes \"x+%3E=+4\" a true inequality. This value is larger than 4. So we will use \"f%28x%29+=+-2x-4\" as our function\r
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\n" ); document.write( "\n" ); document.write( "Plug in x = 7. Use the order of operations PEMDAS to simplify
\n" ); document.write( "\"f%28x%29+=+-2x-4\"
\n" ); document.write( "\"f%287%29+=+-2%287%29-4\" Replace every x with 7
\n" ); document.write( "\"f%287%29+=+-14-4\"
\n" ); document.write( "\"f%287%29+=+-18\"
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