document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135761>Question 1135761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat takes 5 hours to go 25 miles upstream. It can go 50 miles downstream in the same time. Find the rate of the current and the rate of the boat in still water.​ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753423 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> upstream speed against the current, s-c, is 5 mph<BR>\n" );
document.write( "downstream it goes 10 mph, and that is s+c, where s is speed in still water and c the current<BR>\n" );
document.write( "if the two are added<BR>\n" );
document.write( "2s=15<BR>\n" );
document.write( "x=7.5 mph in still water <BR>\n" );
document.write( "c=2.5 mph current </SPAN>\n" );
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