document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135714>Question 1135714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ship is anchored off a long straight shoreline that runs north and south. From two observation points 18 miles apart on shore, the bearings of the ship are N 37° E and S 55° E. What is the distance from the ship to each of the observation points? (Round your answers to one decimal place.)\r<BR>\n" );
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document.write( "distance from northern point    	 <BR>\n" );
document.write( "=               mi\r<BR>\n" );
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document.write( "distance from southern point    	 <BR>\n" );
document.write( "=               mi<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753415 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a triangle is formed.\r<BR>\n" );
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document.write( "the triangle is labeled ABC.\r<BR>\n" );
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document.write( "A is the intersection of 2 lines created from B and C.\r<BR>\n" );
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document.write( "the length of line BC is equal to 18 miles.\r<BR>\n" );
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document.write( "angle C is the south end of the line BC, whose angle is north 37 degrees east.\r<BR>\n" );
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document.write( "aangle B is the north end of the line BC, whose angle is south 55 degrees east.\r<BR>\n" );
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document.write( "the triangle formed is ABC.\r<BR>\n" );
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document.write( "since the sum of the angles of a triangle is 180 degrees, then angle A must be equal to 180 - 37 - 55 = 88.\r<BR>\n" );
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document.write( "once you have this down, then you can use the law of sines to find the length of AC and the length of AB.\r<BR>\n" );
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document.write( "your formula is a / sin(A) = b / sin(B) = c / sin(C).\r<BR>\n" );
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document.write( "a is the side opposite angle A.<BR>\n" );
document.write( "b is the side opposite angle B.<BR>\n" );
document.write( "c is the side opposite angel C.\r<BR>\n" );
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document.write( "a/sin(A) is equal to 18 / sin(88) which is equal to 18.0109718.\r<BR>\n" );
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document.write( "a / sin(A) becomes 18.0109718.\r<BR>\n" );
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document.write( "\the formula becomes 18.109718 = b / sin(B) = c / sin(C).\r<BR>\n" );
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document.write( "solve for b to get b = sin(B) * 18.109718.<BR>\n" );
document.write( "since B = 55 degrees, then b = sin(55) * 18.109718 = 14.75372437 miles.\r<BR>\n" );
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document.write( "solve for c to get c = sin(C) * 18.109718.<BR>\n" );
document.write( "since C = 37 degrees), then c = sin(37) * 18.109718 = 10.83927341 miles.\r<BR>\n" );
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document.write( "your solution should be that the distance from the northern point = c = 10.8 miles and the distance from the southern point = b = 14.8 miles.\r<BR>\n" );
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document.write( "here's what my diagram looks like.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2019/022803.jpg\" alt=\"$$$\" >\r<BR>\n" );
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