document.write( "Question 103591: The height h in feet of an object after t seconds is given by the function
\n" ); document.write( " h = –16t^2 + 40t + 10.
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Algebra.Com's Answer #75337 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To find when the object will hit the ground, let h=0 and solve for t\r
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\n" ); document.write( "\n" ); document.write( "\"0=-16t%5E2+%2B+40t+%2B+10\"\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for t:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"at%5E2%2Bbt%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"-16%2At%5E2%2B40%2At%2B10=0\" ( notice \"a=-16\", \"b=40\", and \"c=10\")
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\n" ); document.write( " \"t+=+%28-40+%2B-+sqrt%28+%2840%29%5E2-4%2A-16%2A10+%29%29%2F%282%2A-16%29\" Plug in a=-16, b=40, and c=10
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\n" ); document.write( " \"t+=+%28-40+%2B-+sqrt%28+1600-4%2A-16%2A10+%29%29%2F%282%2A-16%29\" Square 40 to get 1600
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\n" ); document.write( " \"t+=+%28-40+%2B-+sqrt%28+1600%2B640+%29%29%2F%282%2A-16%29\" Multiply \"-4%2A10%2A-16\" to get \"640\"
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\n" ); document.write( " \"t+=+%28-40+%2B-+sqrt%28+2240+%29%29%2F%282%2A-16%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"t+=+%28-40+%2B-+8%2Asqrt%2835%29%29%2F%282%2A-16%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"t+=+%28-40+%2B-+8%2Asqrt%2835%29%29%2F-32\" Multiply 2 and -16 to get -32
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"t+=+%28-40+%2B+8%2Asqrt%2835%29%29%2F-32\" or \"t+=+%28-40+-+8%2Asqrt%2835%29%29%2F-32\"
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\n" ); document.write( " Now break up the fraction
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\n" ); document.write( " \"t=-40%2F-32%2B8%2Asqrt%2835%29%2F-32\" or \"t=-40%2F-32-8%2Asqrt%2835%29%2F-32\"
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\n" ); document.write( " Simplify
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\n" ); document.write( " \"t=5%2F4-sqrt%2835%29%2F4\" or \"t=5%2F4%2Bsqrt%2835%29%2F4\"
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\n" ); document.write( " So the solutions are:
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\n" ); document.write( " \"t=5%2F4-sqrt%2835%29%2F4\" or \"t=5%2F4%2Bsqrt%2835%29%2F4\"
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\n" ); document.write( "\n" ); document.write( "Since a negative time doesn't make any sense, the only solution is approximately \r
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\n" ); document.write( "\n" ); document.write( "\"t=2.729\"\r
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\n" ); document.write( "\n" ); document.write( "So it will take about 2.729 seconds for the object to hit the ground
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