Algebra.Com's Answer #75337 by jim_thompson5910(35256)  You can put this solution on YOUR website! To find when the object will hit the ground, let h=0 and solve for t\r \n" );
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document.write( " Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for t:
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document.write( " Starting with the general quadratic \n" );
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document.write( " the general solution using the quadratic equation is: \n" );
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document.write( " So lets solve ( notice , , and ) \n" );
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document.write( " Plug in a=-16, b=40, and c=10 \n" );
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document.write( " Square 40 to get 1600 \n" );
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document.write( " Multiply to get  \n" );
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document.write( " Combine like terms in the radicand (everything under the square root) \n" );
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document.write( " Simplify the square root (note: If you need help with simplifying the square root, check out this solver) \n" );
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document.write( " Multiply 2 and -16 to get -32 \n" );
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document.write( " So now the expression breaks down into two parts \n" );
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document.write( " or  \n" );
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document.write( " Now break up the fraction \n" );
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document.write( " or  \n" );
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document.write( " Simplify \n" );
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document.write( " or  \n" );
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document.write( " So the solutions are: \n" );
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document.write( " or  \n" );
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document.write( "Since a negative time doesn't make any sense, the only solution is approximately \r \n" );
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document.write( "So it will take about 2.729 seconds for the object to hit the ground \n" );
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