document.write( "Question 1135693: Company XYZ knows that replacement times for the portable MP3 players it produces are normally distributed with a mean of 4 years and a standard deviation of 0.6 years.\r
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document.write( "Find the probability that a randomly selected portable MP3 player will have a replacement time less than 2.3 years? P(X<2.3 years) = ____\r
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document.write( "Answer accurately to 4 decimals. Answers obtained using exact z-scores or z-scores rounded to 3 decimals places are accepted.\r
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document.write( "If the company wants to provide a warranty so that only 3% of the MP3 players will be replaced before the warranty expires, what is the time length of the warranty? Warranty = ___ years\r
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document.write( "Answer accurately to 1 decimal. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. \n" );
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Algebra.Com's Answer #753357 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "for x<2.3 years, z<=-1.7/0.6=-2.833 \n" ); document.write( "This probability is 0.0023\r \n" ); document.write( "\n" ); document.write( "z-score for 0.03 is -1.881 \n" ); document.write( "-1.881=(x-4)/0.6 \n" ); document.write( "x=2.871 years \n" ); document.write( " \n" ); document.write( " |