document.write( "Question 1135704: Using the vertex (h,k) and a point on the graph (x,y), how do I find the general equation from of:
\n" ); document.write( "(h,k)= (2,0), (x,y)= (4,4) ?
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Algebra.Com's Answer #753353 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the quadratic is written in the form \"y+=+a%28x++-++h%29%5E2+%2B+k\", where the vertex is the point (\"h\", \"k\")\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "(\"h\", \"k\")
\n" ); document.write( "= (\"2\", \"0\")\r
\n" ); document.write( "\n" ); document.write( "and (\"x\", \"y\")=(\"4\", \"4\")\r
\n" ); document.write( "\n" ); document.write( "using vertex, you have\r
\n" ); document.write( "\n" ); document.write( "\"y+=+a%28x++-++2%29%5E2+%2B+0\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+a%28x++-++2%29%5E2+\"\r
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\n" ); document.write( "\n" ); document.write( "now use given point and calculate \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"4=+a%284++-++2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"4=+a%282%29%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"4=+4a+\"\r
\n" ); document.write( "\n" ); document.write( "\"a=1\"\r
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\n" ); document.write( "\n" ); document.write( "so your equation is: \"y+=+1%28x++-++2%29%5E2+\"=>\"y+=+%28x++-++2%29%5E2+\"\r
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