document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103613>Question 103613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (((8/2m-4 + 3/5m-10=1/5))) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75335 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8/(2m-4) + 3/(5m-10) = 1/5\r<BR>\n" );
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document.write( "Factor the denominators:<BR>\n" );
document.write( "8/[2(m-2)] + 3/[5(x-2)] = 1/5\r<BR>\n" );
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document.write( "Least common multiple of the denominators is 10(x-2)<BR>\n" );
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document.write( "Multiply thru by the lcm to get:\r<BR>\n" );
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document.write( "8*5 + 3*2 = 2(x-2)\r<BR>\n" );
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document.write( "13 + 6 = 2x-4<BR>\n" );
document.write( "2x = 23<BR>\n" );
document.write( "x = 23/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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