document.write( "Question 1079104: Gabby is 1 year more than twice Larry's age. 3 years from now, Megan will be 27 less than twice Gabby's age. 4 years ago, Megan was 1 year less than 3 times Larry's age. How old will Megan be 3 years from now?
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Algebra.Com's Answer #753273 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Gabby is 1 year more than twice Larry's age. 3 years from now, Megan will be 27 less than twice Gabby's age. 4 years ago, Megan was 1 year less than 3 times Larry's age. How old will Megan be 3 years from now?
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Let Megan's and Larry's ages be M, and L, respectively
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document.write( "Then Gabby's = 2L + 1
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document.write( "Also, M + 3 = 2(2L + 1 + 3) - 27_____4L = M + 22_____ 
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document.write( "And, M - 4 = 3(L - 4) - 1_____3L = M + 9_____
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document.write( "WIth L being , we can say that: 
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document.write( "3M + 66 = 4M + 36 ------ Multiplying by LCD, 12
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document.write( "3M - 4M = 36 - 66
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document.write( "- M = - 30
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document.write( "Megan's age, or 
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document.write( "In 3 years' time, Megan will be:  \n" );
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