document.write( "Question 1135611: A metallurgist has an alloy with 15​% titanium and an alloy with 25​% titanium. He needs 100 grams of an alloy with 21​% titanium. How much of each alloy should be mixed to attain the 100 grams of alloy with 21​% ​titanium? \n" ); document.write( "
Algebra.Com's Answer #753241 by VFBundy(438)\"\" \"About 
You can put this solution on YOUR website!
x = grams of 15% titanium
\n" ); document.write( "y = grams of 25% titanium
\n" ); document.write( "
\n" ); document.write( "Make two equations:
\n" ); document.write( "\"x+%2B+y+=+100\"
\n" ); document.write( "\"0.15x+%2B+0.25y+=+0.21%28100%29\"
\n" ); document.write( "
\n" ); document.write( "Simplify second equation:
\n" ); document.write( "\"x+%2B+y+=+100\"
\n" ); document.write( "\"0.15x+%2B+0.25y+=+21\"
\n" ); document.write( "
\n" ); document.write( "Multiply second equation by -4:
\n" ); document.write( "\"x+%2B+y+=+100\"
\n" ); document.write( "\"-0.6x+-+y+=+-84\"
\n" ); document.write( "
\n" ); document.write( "Add the equations together:
\n" ); document.write( "\"0.4x+=+16\"
\n" ); document.write( "
\n" ); document.write( "Solve for x:
\n" ); document.write( "\"x+=+40\"
\n" ); document.write( "
\n" ); document.write( "x = 40, so that means the metallurgist uses 40 grams of the 15% titanium. Since x + y = 100 (from our first equation), that means the metallurgist uses 60 grams of the 25% titanium.
\n" ); document.write( "
\n" ); document.write( "
\n" );