document.write( "Question 1135611: A metallurgist has an alloy with 15% titanium and an alloy with 25% titanium. He needs 100 grams of an alloy with 21% titanium. How much of each alloy should be mixed to attain the 100 grams of alloy with 21% titanium? \n" ); document.write( "
Algebra.Com's Answer #753241 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! x = grams of 15% titanium \n" ); document.write( "y = grams of 25% titanium \n" ); document.write( " \n" ); document.write( "Make two equations: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Simplify second equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply second equation by -4: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Add the equations together: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Solve for x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = 40, so that means the metallurgist uses 40 grams of the 15% titanium. Since x + y = 100 (from our first equation), that means the metallurgist uses 60 grams of the 25% titanium. \n" ); document.write( " |