document.write( "Question 1096088: Bob has $8300.00 he invests at a rate of 6.2% interest per year compounded quarterly.
\n" );
document.write( "a) How much does Bob have after 3 and 1/2 years ?
\n" );
document.write( "b) How long will it take for Bob's investment to reach $15,000.00 ? \n" );
document.write( "
Algebra.Com's Answer #753238 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! This is the formula for compound interest: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "N is the new amount. \n" ); document.write( "P is the principal amount. \n" ); document.write( "r is the annual interest rate. \n" ); document.write( "n is how often the interest is compounded per year. \n" ); document.write( "t is the number of years. \n" ); document.write( " \n" ); document.write( "a) How much does Bob have after 3 and 1/2 years ? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------------------------------- \n" ); document.write( " \n" ); document.write( "b) How long will it take for Bob's investment to reach $15,000.00 ? \n" ); document.write( " \n" ); document.write( "Divide each side of the equation by 8300: \n" ); document.write( " \n" ); document.write( "Simplify the stuff inside the parenthesis: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Convert this to log form: \n" ); document.write( "log 1.8072 base 1.0155 = 4t \n" ); document.write( " \n" ); document.write( "Compute log 1.8072 base 1.0155: \n" ); document.write( "38.4744 = 4t \n" ); document.write( " \n" ); document.write( "Solve for t: \n" ); document.write( "t = 9.6186 \n" ); document.write( " \n" ); document.write( "It will take 9.6186 years for Bob's investment to reach $15,000. \n" ); document.write( " |