document.write( "Question 1096088: Bob has $8300.00 he invests at a rate of 6.2% interest per year compounded quarterly.
\n" ); document.write( "a) How much does Bob have after 3 and 1/2 years ?
\n" ); document.write( "b) How long will it take for Bob's investment to reach $15,000.00 ?
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Algebra.Com's Answer #753238 by VFBundy(438)\"\" \"About 
You can put this solution on YOUR website!
This is the formula for compound interest:
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\n" ); document.write( "\"N=P%281%2Br%2Fn%29%5Ent\"
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\n" ); document.write( "N is the new amount.
\n" ); document.write( "P is the principal amount.
\n" ); document.write( "r is the annual interest rate.
\n" ); document.write( "n is how often the interest is compounded per year.
\n" ); document.write( "t is the number of years.
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\n" ); document.write( "a) How much does Bob have after 3 and 1/2 years ?
\n" ); document.write( "\"N=8300%281%2B0.062%2F4%29%5E%284%2A3.5%29\" = $10,294.31
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\n" ); document.write( "b) How long will it take for Bob's investment to reach $15,000.00 ?
\n" ); document.write( "\"15000=8300%281%2B0.062%2F4%29%5E%284t%29\"
\n" ); document.write( "Divide each side of the equation by 8300:
\n" ); document.write( "\"1.8072=%281%2B0.062%2F4%29%5E%284t%29\"
\n" ); document.write( "Simplify the stuff inside the parenthesis:
\n" ); document.write( "\"1.8072=%281.0155%29%5E%284t%29\"
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\n" ); document.write( "Convert this to log form:
\n" ); document.write( "log 1.8072 base 1.0155 = 4t
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\n" ); document.write( "Compute log 1.8072 base 1.0155:
\n" ); document.write( "38.4744 = 4t
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\n" ); document.write( "Solve for t:
\n" ); document.write( "t = 9.6186
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\n" ); document.write( "It will take 9.6186 years for Bob's investment to reach $15,000.
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