document.write( "Question 1135509: A shipment of 102 laptops contains 10 defective laptops. A quality control specialist chooses a sample of 8 laptops from the shipment.\r
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document.write( "a) How many possible choices of 8 laptops can be made?
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document.write( "b) How many of these possible selections will not contain any defective laptops?
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document.write( "c) How many of the possible selections will contain at least one defective laptop?
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document.write( "d) How many of the possible selections will contain exactly one defective laptop? \n" );
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Algebra.Com's Answer #753173 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! a is 102!/94!8! or 102C8=2.19 x 10^11 (2192950683 x 10^11) ANSWER a \n" ); document.write( "No defective ones \n" ); document.write( "92/102*91/101*90/100*89/99*88/98*87/97*86/96*85/95=0.4245 probability that none is defective so a 0.5755 probability at least one is defective. \n" ); document.write( "1-(92C8/102C8)=1.2621418 x 10^11 ANSWER c, at least one defective\r \n" ); document.write( "\n" ); document.write( "That means 9.308088718 x 10^10 ways there are no defective ones ANSWER b\r \n" ); document.write( "\n" ); document.write( "exactly one is 10C1*92C7/102C8= 0.39948 probability or 8.76056 x 10^10 ways ANSWER d \n" ); document.write( "Notice how the top part of the \"choose\" factor (hypergeometric distribution) adds to 102 and the bottom adds to 8. \n" ); document.write( " \n" ); document.write( " |