document.write( "Question 1135530: Two flying drones leave an airport at the same time. The heading of the first is
\n" ); document.write( "120° and the heading of the second 320°. If the drones are traveling at 80 and
\n" ); document.write( "50 mph respectively, how far apart will they be after 1 hour? \n" ); document.write( "

Algebra.Com's Answer #753167 by Boreal(15235) $\"\"$ $\"About$

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Draw this and the first drone is 40 miles south of where it started (sin 30*80) and 40 sqrt (3) miles east.
\n" ); document.write( "The other is cos 50=x/50 or x=50 cos 50=32.14 miles west and 50 sin 50 or 38.30 miles north.
\n" ); document.write( "These are essentially x and y values on the grid or (40 sqrt (30), -40) and (-32.14, 38.3)
\n" ); document.write( "The distance formula can be used for this or sqrt (diff (x)^2+ diff (y)^2)=sqrt((101.42^2+78.3^2))=128.13 miles.
\n" ); document.write( "This is reasonable, since they are almost on reciprocal bearings (140-320 or 120-300 would be), and that distance would be 130 miles. \n" ); document.write( "

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