document.write( "Question 1063903: Jen does one-quarter of a job in 3 hours. If Nicky works 2 hours more than Jen, she can finish one-sixth of the job. How long does it take to do the job if they work together? Thank you. \n" ); document.write( "
Algebra.Com's Answer #753143 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! Jen does one-quarter of a job in 3 hours: \n" ); document.write( "If it takes Jen 3 hours to complete 1/4 of the job, that means it would take her 12 hours to complete the entire job. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If Nicky works 2 hours more than Jen, she can finish one-sixth of the job: \n" ); document.write( "This means Nicky can complete 1/6 of the job in 5 hours. If it takes Nicky 5 hours to complete 1/6 of the job, that means it would take her 30 hours to complete the entire job. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Working together:\r \n" ); document.write( "\n" ); document.write( "Jen's rate = 1/12 job per hour \n" ); document.write( "Nicky's rate = 1/30 job per hour \n" ); document.write( " \n" ); document.write( "TIME * RATE = JOB \n" ); document.write( " \n" ); document.write( "TIME * (1/12 + 1/30) = 1 \n" ); document.write( " \n" ); document.write( "TIME * (5/60 + 2/60) = 1 \n" ); document.write( " \n" ); document.write( "TIME * (7/60) = 1 \n" ); document.write( " \n" ); document.write( "TIME = 60/7 hours\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |