document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135518>Question 1135518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A services station owner wants to mix up some 35 percent antifreeze. He wants to use up his current supply of 100 gallons of 20 percent antifreeze and add enough 40 percent antifreeze to bring the mixture up to 35 percent. How many gallons of 40 percent antifreeze should he add? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753139 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x equal the number of gallons of 40 percent antifreeze.\r<BR>\n" );
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document.write( "100 * .20 + x * .40 = .35 * (x + 100)\r<BR>\n" );
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document.write( "simplify to get 20 + .40 * x = .35 * x + .35 * 100.\r<BR>\n" );
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document.write( "simplify further to get 20 + .4x = .35x + 35.\r<BR>\n" );
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document.write( "subtract 20 from both sides of this euation and subtract .35x from both sides of this equation to get .4x - .35x = 35 - 20.\r<BR>\n" );
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document.write( "simplify to get .05x = 15.\r<BR>\n" );
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document.write( "solve for x to get x = 300.\r<BR>\n" );
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document.write( "100 * .20 + 300 * .40 = 20 + 120 = 140.\r<BR>\n" );
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document.write( "140 / 400 = .35 * 100 = = 35%.\r<BR>\n" );
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document.write( "he will need 300 gallons of 40% antifreeze to mix with 100 gallons of 20% antifreeze to get 400 gallons of 35% antifreeze.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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