document.write( "Question 1135514: axel and dash are brothers they go to the same school.today they left for the school at same time and walked to school .axel walked at speed of 315 feet per minute. dash walked to school at speed of 420 feet per minute.dash arrived 2 minutes before axel.what is the distance in feet between there home and school?
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Algebra.Com's Answer #753136 by ikleyn(52814)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let x be the distance under the question.\r\n" );
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document.write( "Then you have this \"time\" equation\r\n" );
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document.write( "\"x%2F315\" - \"x%2F420\" = 2  minutes.           <<<---=== Every fraction on the left side is the time to cover the distance . . . \r\n" );
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document.write( "To solve it, multiply both sides by 315*420. You wiil get\r\n" );
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document.write( "420x - 315x = 2*315*420\r\n" );
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document.write( "105x = 264600\r\n" );
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document.write( "x = \"264600%2F105\" = 2520 ft.     ANSWER\r\n" );
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document.write( "CHECK.   \"2520%2F315\" = 8 minutes;   \"2520%2F420\" = 6 minutes;   8 - 6 = 2 minutes.   ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "From this solution,  learn on how to write,  how to use and how to solve a  \"time\"  equation.\r
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\n" ); document.write( "\n" ); document.write( "To see many other similar solved problems,  look into the lessons\r
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