document.write( "Question 15154: three exam scores of 70, 60, and 40 what score would you need on the fourth exam to give an average of 72.0 \n" ); document.write( "
Algebra.Com's Answer #7531 by pramboggle(1)\"\" \"About 
You can put this solution on YOUR website!
To find the mean (or average) of a problem you add together the numbers then divide by however many numbers there are. In this case you only have 3 of the 4 numbers you need. Use x for the fourth.\r
\n" ); document.write( "\n" ); document.write( "\"%28%2870%2B60%2B40%2Bx%29%2F%284%29%29=+72\"\r
\n" ); document.write( "\n" ); document.write( "Then yoy want to solve for x. Make the 72 a \"72%2F1\".\r
\n" ); document.write( "\n" ); document.write( "\"%28%2870%2B60%2B40%2Bx%29%2F%284%29%29=+%2872%2F1%29\" Then cross multiply.
\n" ); document.write( "\"%28%28170%2Bx%29%2F4%29=%2872%2F1%29\"
\n" ); document.write( "\"1%28170%2Bx%29=%284%29%2872%29\"
\n" ); document.write( "\"170%2Bx=288\"
\n" ); document.write( "\"x=118\"\r
\n" ); document.write( "\n" ); document.write( "If you want to check your answer you go back and plug in 118 for x. \r
\n" ); document.write( "\n" ); document.write( "\"%2870%2B60%2B40%2B118%29%2F4=72\"\r
\n" ); document.write( "\n" ); document.write( "It works! So 118 is your answer.
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