document.write( "Question 15154: three exam scores of 70, 60, and 40 what score would you need on the fourth exam to give an average of 72.0 \n" ); document.write( "
Algebra.Com's Answer #7531 by pramboggle(1)![]() ![]() ![]() You can put this solution on YOUR website! To find the mean (or average) of a problem you add together the numbers then divide by however many numbers there are. In this case you only have 3 of the 4 numbers you need. Use x for the fourth.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then yoy want to solve for x. Make the 72 a \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you want to check your answer you go back and plug in 118 for x. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It works! So 118 is your answer. \n" ); document.write( " |