document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135405>Question 1135405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jack has 4 more dimes than he has nickles if he has a total of 1.75 in his pocket how many nickels does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #753049 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=753049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Informally....<br><BR>\n" );
document.write( "(1) Count the \"extra\" 4 dimes and set them aside.  The remaining coins are equal numbers of nickels and dimes, with a total value of $1.75-$0.40 = $1.35.<br><BR>\n" );
document.write( "(2) Group the remaining coins in groups of one nickel and one dime each.  The value of each group is $0.15.<br><BR>\n" );
document.write( "(3) The number of groups worth $0.15 each needed to make the remaining $1.35 is 1.35/0.15 = 135/15 = 9; so there are 9 nickels and 9 dimes.<br><BR>\n" );
document.write( "(4) Now bring back in those 4 dimes you set aside at the beginning, to find that the number of nickels in his pocket is 9 and the number of dimes is 13. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );