document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103577>Question 103577</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square.<BR>\n" );
document.write( "	4x^2 + 2x – 3 = 0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75303 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x^2 + 2x – 3 = 0<BR>\n" );
document.write( "x^2+.5x-.75=0 divide the equation by 4 to make the coeficient of the 1st term 1.<BR>\n" );
document.write( "x^2+.5x    =.75<BR>\n" );
document.write( "x^2+.5x+.0625=.75+.0625 Divide the 2nd term by 2 and square the result and make it the new 3rd term and add it to the right side. Now we have a perfect square on the left.<BR>\n" );
document.write( "(x+.25)^2=.8125 factor the left and combine on the right.<BR>\n" );
document.write( "x+.25=+-sqrt(.8125)<BR>\n" );
document.write( "x=-.25+-sqrt(.8125)<BR>\n" );
document.write( "x=-1.1514, x=0.6514<BR>\n" );
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